Correction - Exercice 04 page 180 - Activités algébriques
1ère année secondaire
Activités algébriques
Exercice 04 page 180
Calculons : \(\frac{y}{x}\) ; \(\frac{-x}{y}\) ; \(\frac{-x}{-y}\) ; \(\frac{x}{-y}\) ; \(\frac{x}{3y}\)
On a \(\frac{x}{y}\)\(=\sqrt{2}\)
\(\frac{y}{x}\)\(=\)\(\frac{1}{\frac{x}{y}}\)\(=\)\(\frac{1}{\sqrt{2}}\)
\(\frac{-x}{y}\)\(=\)\(-\sqrt{2}\)
\(\frac{-x}{-y}\)\(=\)\(\sqrt{2}\)
\(\frac{x}{-y}\)\(=\)\(-\sqrt{2}\)
\(\frac{x}{3y}\)\(=\)\(\frac{1}{3}\times\frac{x}{y}\)\(=\)\(\frac{1}{3}\)\(\times\sqrt{2}\)\(=\)\(\frac{1\times\sqrt{2}}{3}\)\(=\)\(\frac{\sqrt{2}}{3}\)
On a \(\frac{x}{y}\)\(=\sqrt{2}\)
\(\frac{y}{x}\)\(=\)\(\frac{1}{\frac{x}{y}}\)\(=\)\(\frac{1}{\sqrt{2}}\)
\(\frac{-x}{y}\)\(=\)\(-\sqrt{2}\)
\(\frac{-x}{-y}\)\(=\)\(\sqrt{2}\)
\(\frac{x}{-y}\)\(=\)\(-\sqrt{2}\)
\(\frac{x}{3y}\)\(=\)\(\frac{1}{3}\times\frac{x}{y}\)\(=\)\(\frac{1}{3}\)\(\times\sqrt{2}\)\(=\)\(\frac{1\times\sqrt{2}}{3}\)\(=\)\(\frac{\sqrt{2}}{3}\)
Libellés:
1ère année secondaire
Activités algébriques
Correction
Corrigées
exercice
Le Mathématicien
manuel scolaire
Math
Aucun commentaire: